Question
In an unusual vernier, 9 vernier scale divisions coincide with 8 main scale division, then what is the least count of the vernier?(A) $(8 / 9) \mathrm{mm}$(B) $(1 / 9) \mathrm{mm}$(C) $(1 / 17) \mathrm{mm}$(D) $(1 / 8) \mathrm{mm}$
Step 1
This means that 8 main scale divisions (M) are equal to 9 vernier scale divisions (V). We can write this as: \[8M = 9V\] Show more…
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