Question
In an usual vernier, 10 vernier scale divisions, coin side with 8 main scale divisions, then what is the least count of the vernier?(A) $0.1 \mathrm{~mm}$(B) $0.2 \mathrm{~mm}$(C) $0.8 \mathrm{~mm}$(D) $(1 / 8) \mathrm{mm}$
Step 1
This means that the length of 10 vernier scale divisions (V) is equal to the length of 8 main scale divisions (M). Mathematically, this can be written as: \[10V = 8M\] Show more…
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