00:01
So for this, we're given a system of equations.
00:04
X minus 4y is equal to negative 11, and x plus 3y is equal to 3.
00:13
We're asked to find the values of x and y using substitution.
00:17
So we can see that we can solve for x pretty easily.
00:22
Let's just look at this one.
00:24
You can say that x is equal to 11 plus...
00:27
Oh, no, no, no, no, no.
00:32
You can say that x is equal to 4y minus 11.
00:37
And so using this, we can substitute in here for x, we have 4y minus 11, place of x plus 3y is equal to 3.
00:50
And so 4y plus 3y is 7y minus 11 equals to 3.
00:58
If we add 11 to both sides, we get 14...