Question
In Exercises 13–24, solve the quadratic equation by factoring.$$x^{2}-2 x-8=0$$
Step 1
We are looking for two numbers that multiply to -8 and add to -2. The numbers that fit this criteria are -4 and 2. Therefore, we can write the equation as follows: $$x^{2}-2 x-8=(x-4)(x+2)=0$$ Show more…
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