Question
In Exercises $15-18,$ write a proof Given $\overline{\mathrm{PQ}}$ bisects $\angle \mathrm{SPT}, \overline{\mathrm{SP}} \cong \overline{\mathrm{TP}}$ Prove $\Delta \mathrm{SPQ} \cong \Delta \mathrm{TPQ}$
Step 1
Step 1: Given that $\overline{\mathrm{PQ}}$ bisects $\angle \mathrm{SPT}$, we can say that $\angle \mathrm{SPQ} \cong \angle \mathrm{TPQ}$ due to the definition of an angle bisector. Show more…
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