1) $(f \circ g)(x) = f(g(x)) = f(-2x + 1)$
Now, we substitute the expression for $f(x)$:
$(f \circ g)(x) = -\frac{1}{2}(-2x + 1) - \frac{1}{2}$
Distribute the $-\frac{1}{2}$:
$(f \circ g)(x) = x - \frac{1}{2} - \frac{1}{2}$
Combine the constants:
$(f \circ g)(x)
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