1) $(f \circ g)(x) = f(g(x)) = f\left(\frac{1}{3}x - \frac{2}{3}\right)$
Now, we substitute the expression for $g(x)$ into the function $f(x)$:
$f\left(\frac{1}{3}x - \frac{2}{3}\right) = 3\left(\frac{1}{3}x - \frac{2}{3}\right) + 2$
Simplify the
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