00:01
All right, so we're given way the function w equals ev plus v delta new squared or wuging g.
00:09
Okay.
00:10
So we're going to get the partial derivative of this function of w with respect to each of the variable on the right hand side.
00:18
So we have variables p, v, delta, new, and g.
00:25
Okay, so let's start with the partial derivative of w with respect to.
00:32
P.
00:33
Okay.
00:34
So for the first term, okay, we have the partial derivative of p -v, okay, with respect to p.
00:42
So that's, we'll treat the other variables as constant, and we'll just get the derivative of each term with respect to p.
00:51
So we have v, a partial derivative of p with respect to p.
00:58
Okay.
00:59
Plus the partial derivative of p with respect to p okay so notice that there uh there is no variable p in this term so put it this whole term as a constant and the derivative of a constant is just zero okay so we're not we're not going to write it here so we have b partial derivative p with respect to p so that's just equal to one therefore we have v okay next the partial derivative of w with respect to v okay so for the first term we got p partial derivative of v with respect to v plus for the second term we'll treat the other variables as constant so we have delta new squared over 2g and then partial derivative of v with respect to v okay so these terms are just equal to one and also this one therefore we have p plus delta b squared over 2g okay next we have the partial derivative w with respect to delta okay now for the first term which is t b we don't have a variable delta so we'll cheat t b as a constant and differentiating that we get zero okay so let's not write that anymore and then we have the second term so we'll treat the other variables as constant so we have v new squared over 2g then partial derivative of delta with respect to delta okay and we know that this is just equal to one hence we have v new squared over 2g okay next we have partial derivative with respect to new the small are v here...