Question
In Exercises 35 - 48, solve the system graphically.$ \left\{\begin{array}{l} y^2 - 4x + 11 = 0\\ \hspace{1cm} -\dfrac{1}{2}x + y = -\dfrac{1}{2}\end{array}\right. $
Step 1
The first equation is a quadratic equation and can be rewritten as $y = \sqrt{4x - 11}$ and $y = -\sqrt{4x - 11}$. The second equation is a linear equation and can be rewritten as $y = \frac{1}{2}x + \frac{1}{2}$. Show more…
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