Question
In Exercises $5-10$ , find an equation for the tangent to the curve at the given point. Then sketch the curve and tangent together.$$y=\frac{1}{x^{3}}, \quad\left(-2,-\frac{1}{8}\right)$$
Step 1
The function is $y=1/x^{3}$. We can rewrite this as $y=x^{-3}$. The derivative of $y$ with respect to $x$ is given by $y'=-3x^{-4}$. Show more…
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