00:01
So for this question, i'm given the function y is equal to x divided by the natural log of x.
00:05
And i want to show two things.
00:07
First, i want to show that this equation satisfies a differential equation.
00:15
X squared y prime is equal to xy minus y squared.
00:23
And also i want to show that satisfies that y of e is equal to e.
00:29
So first to get to this equation, i do need to find my y prime.
00:34
Simplify it, and then i want to multiply it by x squared.
00:37
So first, taking the derivative of this, i need to use my quotient rule.
00:41
So i first take the bottom, multiplied by the derivative of the top, which is just one, minus bottom, bottom times the top, times the derivative of the bottom, which is derivative of the bottom, which is derivative of the bottom, just 1 over x, all over the bottom squared.
01:07
Well, x times 1 over x is just 1.
01:09
So i get natural log of x minus 1 over natural log of x squared.
01:19
And then just dividing this into two different fractions, i get 1 over the natural log of x minus 1 over natural log of x square.
01:31
So that's as far as i can go in terms of simplifying...