Question
In Exercises $5-8,$ show that each function is a solution of the given initial value problem.$$y^{\prime}=e^{-x^{2}}-2 x y \quad y(2)=0 \quad y=(x-2) e^{-x^{2}}$$
Step 1
To do this, we will use the product rule which states that the derivative of a product of two functions is the derivative of the first function times the second function plus the first function times the derivative of the second function. Show more…
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