00:01
In this problem we're given a function f where f is x to 2 3 times 3 minus 6 in interval negative 2 to 2.
00:08
We're asked to find the critical points, we're asked to plot the function, find the absolute minimum or the maximum and maybe plot the derivative as well.
00:16
So let's start with finding the critical points.
00:19
To do that, let's first find the derivative.
00:21
Given f we find the derivative to be 2x negative 1 3, minus 5 over 3, x 2 3, 2 3, 2 3 and 2 2 3.
00:29
And we can actually write this one as 1 third x to the power negative 1 3rd multiplied by 6 maybe 5x and let's set this to 0 to find the critical point first of all we can see that when x is 0 we get a division by 0 so this makes f prime undefined and x0 actually isn't a given interval so this is a critical point now let's find the values that makes f prime 0 so let's set 6 minus 5 x to be 0.
01:04
From this we find x to be 6 over 5 or 1 .2.
01:11
This also is in the given interval.
01:13
So this is our second critical point...