Doruk Isik

Numerade Educator

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Educator Statistics

Numerade tutor for 7 years
1170 Students Helped

Topics Covered

Differential Equations Made Simple: Expert Tips & Resources
Exploring the World of Derivatives: A Comprehensive Guide
Breaking Limits: Unlock Your Potential with Our Expert Solutions
Stand Out with Differentiation Strategies | Boost Your Business
Polar Coordinates: Understanding the Basics and Applications
Unlock the Power of Vectors: Discover Their Limitless Possibilities
Mastering Equations and Inequalities: Your Guide to Mathematical Success
Unlock the Power of Sequences: Boost Your Productivity
Discover the Best Series to Binge-Watch | Your Ultimate Guide
Unlocking the Power of Functions: Boost Your Programming Skills
Applications of the Derivative
Mastering Integrals: Tips and Tricks for Calculus Success
Applications of Integration: Exploring Real-World Solutions

Doruk's Textbook Answer Videos

01:56
Calculus: Early Transcendentals

(a) Find $ y' $ by implicit differentiation.
(b) Solve the equation explicitly for y and differentiate to get $ y' $ in terms of $ x. $
(c) Check that your solutions to part (a) and (b) are consistent by substituting the expression for $ y $ into your solution for part (a).

$ 9 x^2 - y^2 = 1 $

Chapter 3: Differentiation Rules
Section 5: Implicit Differentiation
Doruk Isik
02:43
Calculus: Early Transcendentals

(a) Find $ y' $ by implicit differentiation.
(b) Solve the equation explicitly for y and differentiate to get $ y' $ in terms of $ x. $
(c) Check that your solutions to part (a) and (b) are consistent by substituting the expression for $ y $ into your solution for part (a).

$ 2x^2 + x + xy = 1 $

Chapter 3: Differentiation Rules
Section 5: Implicit Differentiation
Doruk Isik
02:33
Calculus: Early Transcendentals

(a) Find $ y' $ by implicit differentiation.
(b) Solve the equation explicitly for y and differentiate to get $ y' $ in terms of $ x. $
(c) Check that your solutions to part (a) and (b) are consistent by substituting the expression for $ y $ into your solution for part (a).

$ \sqrt{x} + \sqrt{y} = 1 $

Chapter 3: Differentiation Rules
Section 5: Implicit Differentiation
Doruk Isik
02:22
Calculus: Early Transcendentals

(a) Find $ y' $ by implicit differentiation.
(b) Solve the equation explicitly for y and differentiate to get $ y' $ in terms of $ x. $
(c) Check that your solutions to part (a) and (b) are consistent by substituting the expression for $ y $ into your solution for part (a).

$ \frac {2}{x} - \frac {1}{y} = 4 $

Chapter 3: Differentiation Rules
Section 5: Implicit Differentiation
Doruk Isik
01:10
Calculus: Early Transcendentals

Find $ dy/dx $ by implicit differentiation.

$ x^2 - 4xy + y^2 = 4 $

Chapter 3: Differentiation Rules
Section 5: Implicit Differentiation
Doruk Isik
01:01
Calculus: Early Transcendentals

Find $ dy/dx $ by implicit differentiation.

$ 2x^2 + xy - y^2 = 2 $

Chapter 3: Differentiation Rules
Section 5: Implicit Differentiation
Doruk Isik
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