In this case, $\lambda = 3$. So, we have
$$
A - \lambda I = \left[\begin{array}{ccc}{4-3} & {2} & {3} \\ {-1} & {1-3} & {-3} \\ {2} & {4} & {9-3}\end{array}\right] = \left[\begin{array}{ccc}{1} & {2} & {3} \\ {-1} & {-2} & {-3} \\ {2} & {4} &
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