00:02
Hello, we are given the equation y squared minus 4 x is equal 0 and we know that this is a parabola because one of the one of the variables is squared and one is not one does not have a square term so since we're talking about a parabola parabola we refer to theorem 101 that talks about parabolas.
00:46
Let's put it here in this one here, right? so this has not yet been written in standard form, but we can say which one of these is going to be applicable here.
01:02
Is the term containing x squared or the one containing y? the one containing y so it's going to have a horizontal axis which means that we can eliminate this situation here right we're going to have a parabola with a horizontal axis it's either going to open left or right once we write it in standard form we'll find it's h and k for the vertex and then the focus will be to the left or to the right by p units and the directrix will be a vertical line p units to the left or to the right depending on where this parabola opens who now let's see what we can do we can write this as we can write this we're going to attempt to write this in the standard form so if we take the all the term containing y squared minus 4 y we are going to and transfer this to the other side we'll add 4x to the other side say this 4x right what do we need what do we need to add what do we need to add here what do we need to add here to make this a perfect square so look if we have two terms that are subtracted and squared we will have the square of the first plus the square of the second minus double the product of the two.
02:49
So this would be two times the first which is y times what? this is two times two times two, right? so our second term is two which means we add two squared and we take away two squared.
03:08
Because we don't want to change the value of the expression on the left -hand side.
03:14
Now we interpret, we recognize this to be y -minus 2 squared.
03:22
This is called completing the square.
03:30
Okay, and what do we do with this term? we added to both sides, so it comes to this side here.
03:43
We have the left side covered.
03:45
Now we need to show, we need to factor this.
03:49
So this is going to be four, we factor out four and x plus one.
03:53
And there we have our standard form as we wanted it, as it was listed in theorem four.
04:03
Now, this is y minus k.
04:08
This is x minus h.
04:10
So h is equal minus one and k is equal to two.
04:16
4 is 4 is equal to 4 p.
04:22
See 4p? so dividing by 4 we have p equals 1.
04:33
What are we going to have? p is positive.
04:37
It's greater than 0.
04:38
So this is the situation we will have.
04:41
We forget about the one that turns to the left.
04:44
So, if i have the vertex, the vertex is going to be at, where do we say, hk is minus 1, minus 1 2.
04:58
I am going to plot minus 1 2 as my vertex and through that, through that vertex, i will draw a vertical and a horizontal line, lines that are parallel to the axes...