00:01
In this problem, we have a capacitor with circular plates connected to an emf source.
00:06
And we have that the maximum value of the displacement current is 7 .6 micro -amperts.
00:14
And we neglect the fringing of the electric field at the edge of the plates.
00:19
We want to know what is the maximum value of the current in the circuit.
00:24
So at any instant, its placement current id in the gap between the plates is equal to the conductor conduction current i in the wires.
00:39
So we have id equals i.
00:43
So we have that the maximum value will be the maximum value of the current i max.
00:51
And this is 7 .6 microse.
00:55
For part b, we want to know what is the maximum value of the variation of the electric flux.
01:05
We can write the variation of the electric flux in terms of the induced current, displacement current.
01:13
So we have d5dt max is equal to imax divided by epsilon 0.
01:24
And we have the value here, so this is 7 .6, 10 to the minus 6, and the epsilon is 8 .85 times 10 to the minus 12.
01:35
And this gives us 8 .59 times 10 to the 5 volts, meters, divided by seconds.
01:47
Now for part c, you want to know what is the separation between the plates.
01:52
So we can find the separation between the plates because we know the variation of the potential...