00:01
For this problem on the topic of magnetism, we have a capacitor with circular plates of radius 18 centimeters connected to a source of emf, where the emf amplitude is 220 volts and the angle of frequency 130 radiance per second.
00:13
The maximum value of the displacement current is 7 .6 microampers, and we want to find the maximum value of the current in the circuit, the maximum value of the rate of change of electric flux through the region between the plates, the separation d between the plates, as well as the maximum value of the magnitude of the magnetic field between the plates at a distance of 11 centimeters from the center.
00:37
Now for a, at any instant, the displacement current id in the gap between the plates equals the conduction current in the wires.
00:45
And so the maximum current in the circuit imax is equal to the maximum displacement current id max, which is as given 7 .6 microampiers.
01:02
Now for part b, we know that the displacement current id is equal to the constant epsilon not times the rate of change of electric flux, defy, dt, which means that the maximum displacement or rather the maximum electric flux, d -fi -d -t -max, is equal to the maximum displacement current divided by epsilon -0.
01:32
If we put our values in, this is 7 .6 times 10 to the minus 6 amperes divided by 8 .85 times 10 to the minus 12 ferrets per meter.
01:50
This gives the maximum rate of change of electric flux between the plates to be 8 .59 times 10 to the power of 5 volt meters per second.
02:09
For part c, we let the plate area be a and a plate separation bd.
02:16
The displacement current is id, which is epsilon knot, d5, d t, which is, epsilon not times d by d t and we can write the electric flux as the area a times the electric field e and so this can be written as epsilon not a times d by d t of v over d which we can write as epsilon not a over the plate separation d times d v d t now the potential difference of the capacitor is the same in magnitude as the emf of the generator.
03:06
So we know that v is equal to the emf amplitude, epsilon m times the sine of omega -t, which means that dv -d -t is equal to omega -epsalon -m cosine -omegat -t.
03:27
And so the displacement current id is equal to epsilon -0, a omega -ephsoulon m over d times the cosine of omega -t and the maximum displacement current therefore by letting the cosine term go to one is epsilon not a omega -epsoulon -m over d.
03:55
That means that the plate separation d is equal to epsilon not a omega -epsalon -m divided by the maximum displacement current id max...