00:02
In this question, we have three medium.
00:04
So initially light travels in medium one, and hits the n1n2 interface, and then some of the light get reflected back, and then some light reflects through, and then when it reaches the reflected light reaches the n2 -n3 boundary, it undergoes total internal reflection, is incident at a critical angle.
00:33
So this is data c for n2 and 3 interface.
00:38
So looking at this, we can know that this angle here would be 90 degrees minus data c.
00:52
So to solve part a, is to find the incident angle in medium 1.
01:00
Okay, we'll be using snell's law.
01:08
Okay, we say that n1, sine theta 1 equals to n2, side data 2, so for medium 1 to medium 2, the equation would be n1, sine data equals to n2, xi 90 degrees minus data c okay and you can simplify this to be oxide data c and then for medium two to medium three the equation would be n2 side data c equals to n3 sine 90 degrees.
02:10
Which means that sine data c is n3 divided by n2.
02:19
So we are given that n1 is 1 .6, 0.
02:27
N2 is 1 .40...