00:01
To begin solving this linear programming problem, we have our objective function up here written out from the problem, and we also have our constraints here that we need to graph.
00:11
So we know that this will be in the first quadrant because x and y are both greater than are equal to zero.
00:17
And we want to graph these two functions down here.
00:20
So i want to start by rewriting these into my y -equals mx plus b form, just to make it easier to graph.
00:27
So this first one, we can subtract 2x for both sides to get 3y is greater than or equal to negative 2x plus 6.
00:37
Divide both sides by 3, and we end up with y is greater than or equal to negative 2 thirds x plus 2.
00:46
Now if i want to graph that, my y intercept is at 2.
00:53
And going with the negative two -third slope, my x intercept would be at 3.
01:02
And graph x plus y is less than or equal to 8.
01:05
We can do something similar, or we take y is less than or equal to negative x plus 8.
01:12
So our y intercept would be at 8, and with a slope of negative 1, our x intercept also occurs at 8...