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Problem 28 .2, we have the bore model of hydrogen atom, which the electron moves in a circular orbit of radius 5 .3 times 10 to the negative 11 meters.
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That's this vector here, r, with the speed of 2 .2 times 10 to 6 meters per second.
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That's this vector b.
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And we're reviewing the atom in such a way that electrons over in the plane of paper with the electron moving clockwise.
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We find the magnitude and direction of the electric and magnetic fields at the point produced by the particle.
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Okay, so let's start with the magnetic field, magnetic field.
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So we start with the equation for the magnet field of a moving point charge.
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So that's going to be b is equal to mu not over 4 pi.
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And then we have qv, sine, phi over r squared.
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Okay, so what we need to do is we need to first write in what the charge of the lauchan is.
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So that's just going to write down as qe.
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So mu not over 4 pi.
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And then we write down what v is.
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That's just a number that we're given.
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And then sine of phi is something we need to figure out.
01:25
So sine of phi, that phi represents the angle between the vector b and r.
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And so since that is negative degrees, we have sine of pi over two, which comes out to be one.
01:45
Okay? and we also have v in here, slash this number again...