Question
In the circuit in Fig. $\mathbf{E} 25.47,$ find (a) the rate of conversion of internal (chemical) energy to electrical energy within the battery; (b) the rate of dissipation of electrical energy in the battery; (c) the rate of dissipation of electrical energy in the external resistor.
Step 1
We can do this using Ohm's Law: V = IR where V is the voltage across the battery, I is the current, and R is the total resistance in the circuit. The total resistance is the sum of the internal resistance of the battery (r) and the external resistance Show more…
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In the circuit in $\textbf{Fig. E25.47}$, find (a) the rate of conversion of internal (chemical) energy to electrical energy within the battery; (b) the rate of dissipation of electrical energy in the battery; (c) the rate of dissipation of electrical energy in the external resistor.
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