00:01
Hi, in the given problem, the two cells are sending the current in the circuit in the same direction.
00:13
Here this is terminal b, internal resistance of the cell 1 .6 om, emf of this cell, 16 .0 volt.
00:24
Terminal a, an external resistance of 5 .0 oom, then another cell, having internal resistance 1 .4 oom and the emf of 8 .0 volt terminal c and another external resistance of 9 .0 om between b and c.
00:59
In the first part of the problem we have to find the net current the magnitude of current and its direction passing through this circuit.
01:09
So as both the sources of current means cells are sending their current in the same direction.
01:41
And what is the direction? clockwise.
01:46
So net dmf will be given by their addition, addition of their individual emf.
01:54
So e is equal to 16 .0 plus 8 .0.
02:01
Volt...