In the description of a hypergeometric distribution $X$, given just before Exercise 11, we see that the sample of size $n$ is taken without replacement. If the sample were taken with replacement, $X$ would be binomial with parameters $n$ and $p=r / N$. If $n$ is small relative to $N$, there is not much difference between the two methods of sampling, so a hypergeometric random variable can be approximated by a binomial random variable with parameters $n$ and $p=r / N$. (The usual rule of thumb is that $n$ should not exceed 5 percent of $N$.) Let $X$ be a hypergeometric random variable with parameters $n=5, N=500$, and $r=20$. Calculate the probability that $X=2$ and the binomial approximation to this probability.