This is done by checking if both $np$ and $n(1-p)$ are greater than 5.
Given that $n=500$ and $p=0.1$, we calculate:
$np = 500 \times 0.1 = 50$
$n(1-p) = 500 \times (1-0.1) = 450$
Since both values are greater than 5, it is appropriate to use the normal
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