00:01
In this problem, we're asked to identify the results of reacting each of these substances with excess hydrochloric acid.
00:06
In the case of a terminal alkine, a terminal alkyne reacting with a hydrohalogen will always form a geminal halide.
00:17
So we will have two of the halogen attached at the more substituted position of the alkyne or the position one deep in in the case of a terminal alkyne.
00:25
In the case of a non -terminal alkyne, we have to consider, of course, that this happens in two steps.
00:32
First, we have a reaction of a hydrohologination of an alkyne, so it becomes an alkyne with one halogen attached, and then we react, again, hydrohologonation of an alken, and we must ask, well, this is a markovnikov edition, which position already has more hydrogen, which is, of course, this position...