In the text, the equation
$$\Delta G=\Delta G^{\circ}+R T \ln (Q)$$
was derived for gaseous reactions where the quantities in $Q$ were expressed in units of pressure. We also can use units of $\mathrm{mol} / \mathrm{L}$ for the quantities in $Q$, specifically for aqueous reactions. With this in mind, consider the reaction
$$\mathrm{HF}(a q) \rightleftharpoons \mathrm{H}^{+}(a q)+\mathrm{F}^{-}(a q)$$
for which $K_{\mathrm{a}}=7.2 \times 10^{-4}$ at $25^{\circ} \mathrm{C}$. Calculate $\Delta G$ for the reaction under the following conditions at $25^{\circ} \mathrm{C}$.
a. $[\mathrm{HF}]=\left[\mathrm{H}^{+}\right]=\left[\mathrm{F}^{-}\right]=1.0 \mathrm{M}$
b. $[\mathrm{HF}]=0.98 M,\left[\mathrm{H}^{+}\right]=\left[\mathrm{F}^{-}\right]=2.7 \times 10^{-2} M$
c. $[\mathrm{HF}]=\left[\mathrm{H}^{+}\right]=\left[\mathrm{F}^{-}\right]=1.0 \times 10^{-5} \mathrm{M}$
d. $[\mathrm{HF}]=\left[\mathrm{F}^{-}\right]=0.27 M,\left[\mathrm{H}^{+}\right]=7.2 \times 10^{-4} M$
e. $[\mathrm{HF}]=0.52 M,\left[\mathrm{~F}^{-}\right]=0.67 M,\left[\mathrm{H}^{+}\right]=1.0 \times 10^{-3} M$
Based on the calculated $\Delta G$ values, in what direction will the reaction shift to reach equilibrium for each of the five sets of conditions?