00:01
Number 88 is, in part, a mechanism problem.
00:07
It also is in part a second order integrated rate law problem.
00:13
From the mechanism, it asks us to determine the molecularity for each of the elementary steps.
00:19
So i'll rewrite the first elementary step, which was identified to be slow, because there's only one reactant with a coefficient of one.
00:27
This is unimolecular.
00:29
For the next one, we have two reactants, each with a coefficient of, of 1.
00:33
This is the fast step.
00:35
It's bi -molecular.
00:37
So the rate law then should be for the slow step, rate equals k, multiplied by the concentration, the reactant in the slow step, squared, sorry, not squared, just raised to the first power because we have a coefficient here of 1.
00:59
This is exactly what b tells us, where doubling the concentration doubles the rate, doubling the concentration of the nico4 ended up doubling the rate, which is what would occur if it were first order.
01:16
And then it says if we double the l concentration, l found in the second step, nothing happened, so it must be zero order with respect to l...