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In the theory of relativity, the mass of a particle withvelocity $v$ is$$m=\frac{m_{0}}{\sqrt{1-v^{2} / c^{2}}}$$where $m_{0}$ is the mass of the particle at rest and $c$ is thespeed of light. What happens as $v \rightarrow c^{-} ?$
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Step 1: We are given the equation for the mass of a particle with velocity $v$ in the theory of relativity: $$ m=\frac{m_{0}}{\sqrt{1-v^{2} / c^{2}}} $$ where $m_{0}$ is the mass of the particle at rest and $c$ is the speed of light. Show more…
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Limit of a Function
Limits That Involve Infinity
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