In the theory of relativity, the mass of a particle with velocity $ v $ is $$ m = \frac{m_0}{\sqrt{1 - v^2/c^2}} $$ where $ m_0 $ is the mass of the particle at rest and $ c $ is the speed of light. What happens as $ v \to c^- $?
Added by Logan W.
Step 1
Step 1: Substitute $ v = c $ into the equation for mass $ m $: $$ m = \frac{m_0}{\sqrt{1 - c^2/c^2}} = \frac{m_0}{\sqrt{1 - 1}} = \frac{m_0}{\sqrt{0}} $$ Show more…
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