Question
In $\triangle C D E, \mathrm{m} \angle D=125, \mathrm{m} \angle E=28,$ and $d=12.5 .$ Find $c$ to the nearest hundredth.
Step 1
We know that the sum of the angles in a triangle is $180$ degrees. So, we subtract the sum of angles $D$ and $E$ from $180$ to find angle $C$: \[C = 180 - (D + E) = 180 - (125 + 28) = 27 \text{ degrees}\] Show more…
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