Question
In young's double slit experiment, phase difference between light waves reaching 3rd bright fringe from central fringe with, is $(\lambda=5000 \AA)$(A) zero(B) $2 \pi$(C) $4 \pi$(D) $6 \pi$
Step 1
Step 1: In Young's double slit experiment, the phase difference between light waves reaching any fringe from the central fringe is given by the formula: \[ \Delta \phi = m \cdot 2\pi \] where \( m \) is the order of the fringe. Show more…
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n Young's double slit experiment, the phase difference between the light waves reaching third bright fringe from the central fringe will be (lambda =6000 Å ) (a) Zero (b) 2pi (c) 4pi (d) 6pi
In Young's double slit experiment, a minimum is obtained when the phase difference of super imposing waves is (a) zero (b) $[2 n-1) \pi$ (c) $n \pi$ (d) $(n+1) \pi$of prism is $1^{\circ}$. The fringe width with light of wavelength 6000 A will be (a) $3 \mathrm{~cm}$ (b) $0.011 \mathrm{~cm}$ (c) $2 \mathrm{~cm}$ (d) $4 \mathrm{~cm}$
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Round 2
In young's double slit experiment the phase difference is constant between two sources is $(\pi / 2)$. The intensity at a point equidistant from the slits in terms of max. intensity $\mathrm{I}_{0}$ is (A) $3 \mathrm{I}_{0}$ (B) $\left(\mathrm{I}_{0} / 2\right)$ (C) I_{0 } (D) $\left(3 \mathrm{I}_{0} / 4\right)$
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