00:03
So we're looking at a chemistry program, i mean, a problem, and we have endium oxide.
00:08
And how, in indian oxide, it has 4 .78, 4 grams of end up in every one ground of oxygen.
00:17
So when medellee in 1869, first presented his version of the period of table, he proposed a formula i -n -203 for indian -oxide.
00:26
However, before he presented it to be i -n -203, we thought it was actually i -n -o.
00:42
What values for the atomic mass of end -dium are obtained using these two? formulas.
00:49
So if we're looking at i .n .o.
00:51
First, so i .o is correct.
00:53
Then we're going to have one atomic mass of in to combine with one at tummy mass of o.
01:01
That looks mathematically like this...