00:01
Problem 13.
00:03
Let's begin with a.
00:05
We need to find the missing symbol in a couple of reactions.
00:10
So in a, we have the following.
00:15
Qm24 plus carbon 612 becomes nitrogen 715 plus something else.
00:29
So the rule here is that all the atomic mass number need to be equivalent on each side and all the number of protons need to be equivalent to.
00:42
So we have 4 plus 12 equals 15 plus x, well x equals 1.
00:56
That's for the atomic mass number.
00:58
And then below for the number of protons we have 2 plus 6 equals 7 plus x.
01:06
So x equals 1 again, which means that our main number of protons.
01:09
Mystery atom here is, well, we know it has 1 -1, and then the atom that has one proton is called hydrogen.
01:24
In b, we have hydrogen, but with two nucleons, we have hydrogen with three nucleons, which becomes helium, 4, plus a mystery atom again.
01:49
So 2 plus 2 is 5, minus 4, that's 1.
01:53
1 plus 1 is 2 minus 2 is 0 so we need to find something that has 0 protons but 1 nucleon that's a neutron in c neutron plus uranium 235 becomes xenon 140 plus 240 plus 2 neutrons plus our mystery atom so 1 plus 235, that's 236.
02:47
This one i write it down because it's a little more complex...