Question
$\int_{0}^{\pi / 2} \sin ^{99} x \cos x d x$ is equal to(a) $\frac{1}{99}$(b) $\frac{\pi}{100}$(c) $\frac{99}{100}$(d) None of these.
Step 1
We can simplify this integral by using a substitution. Let $u = \sin x$. Show more…
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