00:01
Hello, today we are doing problem 9 .44, and this problem asks us to explain the absorbed trend in the melting points for the following three isomeric alcohols.
00:10
So we see this molecule here having the lowest melting point with negative 108 degrees, and this is a primary alcohol.
00:20
In the middle, we have another primary alcohol with the melting point of minus 90 degrees.
00:24
In the last one, we have a tertiary alcohol with plus 26 degrees.
00:28
So a trend to remember for melting points and boiling points is that your melting points and in turn your boiling point will increase with the degree of your alcohol.
00:42
So primary will have the lowest melting and boiling point while a tertiary alcohol will have the highest melting and boiling point.
00:50
But now if we were to look at these isomers with the same number of carbons, obviously we know that the tertiary alcohol would have the highest melting point.
01:02
But now these two other examples have both primary alcohols with the same number of carbon.
01:09
So how do we determine which one will have a higher or lower melting point? well, now we need to determine the intermolecular forces and their symmetry.
01:17
So if you see the molecule on the left, it has a lower poiling point than the molecule in the middle...