00:01
In this problem, given that a reaction has an activation energy, ea, equals to 363 kilojoules.
00:37
And the rate constant has to increase 10 -fold, then we have to calculate activation energy of the catalyzed reaction.
00:59
Suppose k1 and k2 are rate constant for activation energy ea1 and ea2 respectively.
02:05
Given temperature, t equals to 25 degrees c, which is equal to 25 plus 270, 3.
02:19
Kelvin equals to 298 kelvin.
02:36
From arrhenius equation, ln k1 equals to lna -1 minus e -a1 divide by rt.
03:17
Consider this as equation 1, ln k2 equals to lna.
03:28
Here, a is frequency factor minus ea2 divide by rt.
03:34
By rt...