00:01
So here in this question we are looking at the three different properties of the following particles.
00:08
First is the k -on, which is a mizon, and the lambda node particle, which is a baryon.
00:15
And the three different properties that we're looking at is actually strangeness, barion number, and finally charge.
00:23
In our case, the properties of the particles is known to be the following, that is the stringence.
00:31
The strangeness value of k -on is 1.
00:33
For lambda 0 is minus 1.
00:37
So this is positive 1.
00:39
Barron number is 0 for the k -on and plus 1 for the lambda 0.
00:48
Finally, the charge for both particles is 0.
00:51
They are both neutral.
00:53
Now we are given that the constituent quark content for k -on is down with an anti -strange.
01:06
On the other hand for the lambda baron it is made up of up, down and strange quark.
01:14
And we want to see whether their properties can be re -established by simply looking at the quark properties.
01:28
So the quark properties we're first going to look at would be the mizons, for the kons, quarks which is down and anti -strange so for down particle has zero strangeness it has a variable number of one -third it has a charge of minus one -third for the for the strange as a stranger's of plus one barren number of minus one third since it is an anti quark charge of plus 1 .3e.
02:17
And we see that the charge itself will cancel out to give us 0, that is good.
02:21
The burial number will cancel out to give us 0, which is also good...