Lead consists of four naturally occurring isotopes. Calculate the atomic mass for lead using the weighted average mass method. (4.5)
$$
\begin{array}{|l|l|l|}
\hline \text { Isotope } & \text { Mass (amu) } & \text { Abundance (\%) } \\
\hline{ }_{82}^{204} \mathrm{~Pb} & 204.0 & 1.40 \\
\hline{ }_{82}^{206} \mathrm{~Pb} & 206.0 & 24.10 \\
\hline{ }_{82}^{207} \mathrm{~Pb} & 207.0 & 22.10 \\
\hline{ }_{82}^{208} \mathrm{~Pb} & 208.0 & 52.40 \\
\hline
\end{array}
$$