Question
Let $a, b, c$ be the sums of the first $n$ terms, next $n$ terms and next n terms of a GP respectively. Then $a, b, c$ are in(a) $\mathrm{AP}$(b) $\mathrm{GP}$(c) $\mathrm{HP}$(d) AGP
Step 1
Then the sum of the first $n$ terms is given by \[S_n = a \frac{r^n - 1}{r - 1}\] So, $a = a \frac{r^n - 1}{r - 1}$. Show more…
Show all steps
Your feedback will help us improve your experience
Gaurav Kalra and 79 other Calculus 2 / BC educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
if $\frac{1}{b-a}+\frac{1}{b-c}=\frac{1}{a}+\frac{1}{c}$, then $a, b, c$ are in (a) AP (b) $\mathrm{GP}$ (c) HP (d) AGP
If $a_{1}, a_{2}, a_{3} \ldots$ are in HP and $f(k)=\sum_{r=1}^{n} a_{r}-a_{k}$, then $\frac{a_{1}}{f(1)}, \frac{a_{2}}{f(2)}, \frac{a_{3}}{f(3)}, \ldots \frac{a=}{f(n)}$ are in (a) AP (b) GP (c) HP (d) AGP
If $\mathrm{a}, \mathrm{b}, \mathrm{c}$ are in $\mathrm{AP}$, then $\mathrm{b}+\mathrm{c}, \mathrm{c}+\mathrm{a}, \mathrm{a}+\mathrm{b}$ are in (a) AP (b) HP (c) GP (d) AGP
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD