Question
Let $f(x)=\min \left\{\sin ^{-1} x, \cos ^{-1} x, \frac{\pi}{6}\right\}, x \in[0,1]$ If areabounded by $y=f(x)$ and $X$ -axis, between the lines $x=0$ and $x=1$ is $\frac{a-X}{b(\sqrt{3}+1)}$. Then, $(a-b)$ is ............
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We need to find the area bounded by $y=f(x)$ and the $X$ -axis, between the lines $x=0$ and $x=1$. Show more…
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