00:01
We just have a tangent line problem.
00:03
And any time you have a tangent line, you need a point, which they give you the point in part b.
00:09
Actually, they don't give you the point.
00:15
We have to find the point, and we also need to find the slope.
00:18
So in part a, they give us the function is equal to x squared plus 6x.
00:30
So in order to find the derivative f prime, we need to take.
00:35
The limit as h approaches 0 of f of x plus h minus f of x all over h.
00:44
Now, re -looking at that problem, that h, we can't do anything.
00:53
We already know that f of x is equal to x squared plus 6x.
00:58
And what we need to do is figure out what f of x plus h is.
01:01
Well, we figure that out by replacing both of these xs with x plus h.
01:07
So it's still squared, and then six, and replace the.
01:10
This x with x plus h so as you go to simplify i'll go ahead and simplify all this uh we would foil out because it's x plus h times x plus h so there's two xh in there plus h squared also need to distribute that six in there and then distribute the minus and what you'll notice hopefully you notice you can show all the work if you need to the x squared cancels six x cancels and every other piece has at least one h in it that we could cancel out with this h in the denominator.
01:49
So the derivative for part a is literally just 2x.
01:58
And if we plug in 0 for this h, we get zero so you don't have to write that down plus 6.
02:05
I don't know if you can see.
02:06
There's a 6 right there with that.
02:08
So there's the equation of the derivative of f of x, 2x plus 6...