00:01
On x between 0 and power 2, we know that sine of x is between 0 and 1.
00:05
Higher powers are smaller.
00:08
So the sign of, the sign to 2n plus 1 of x would be between sine to the 2n x and sign to the 2n plus 2x, with the higher power being smaller.
00:32
And if you integrate all parts, then i sub 2n plus 1 would be between i sub 2n plus 2 and 2n.
00:51
Using the reduction formula, i sub n is equal to n minus 1 over n times i sub n minus 2.
00:58
And if we let n be equal to 2n plus 2, then i sub 2n plus 2 would be equal to 2n plus 1 over 2n minus 2n plus 2 times i sub n plus 2 .0.
01:10
So i sub 2n plus 2 over i sub 2n is equal to 2n plus 1 over 2n plus 2n plus 2n.
01:27
From par a, we know that i sub 2n plus 1 is between i sub 2n plus 2 and i sub 2n.
01:33
And we can divide by i sub 2n.
01:35
So i sub 2n plus 2 divided by i sub 2n would be less than or equal to i sub 2 n plus 1 over i sub 2n...