00:01
All right, so we are saying that our vector set is the set of all positive real numbers.
00:13
And the addition and scalar multiplication are redefined.
00:23
So now addition on this vector set is defined as.
00:37
Multiplication in the real normal number system.
00:46
And scalar multiplication is redefined as the exponent of the number.
01:02
So is this closed? well, let's just go in order.
01:06
Let's try for or does it meet all of the axioms in order to be a vector space? that's what i meant to say.
01:15
So let's look at axiom one.
01:18
Axiom one states for closure under addition.
01:22
So if i take, and i just realized i didn't write this correctly up here, there we go, if i take x1 plus x2, just some general x1 and some general x2, that's going to equal x1 times.
01:59
X2.
02:00
If this is a real number, positive number, and this is a positive number, or positive times a positive makes a positive.
02:14
And it can't be zero because the only way to get zero is to multiply by zero.
02:21
So this is satisfied.
02:30
A2.
02:34
Closure under scalar multiplication.
02:37
So if i take a constant times a positive real number where c does not have to be a positive real number, i'm trying to look at this to see exactly how c is defined.
02:58
Let me read it again, but i think c can be any real number.
03:03
Note that multiplication and exponentation appearing on the right side of these formulas refer to the ordinary operations of real number.
03:11
On real numbers.
03:15
Okay, so c, or in this case, k, can be positive or negative or zero.
03:24
So this is going to give me x sub 1 to the k power.
03:31
Well, x sub 1 to the k power, if k is greater than 1, is a real number.
03:45
And even if it's less than 1, by greater than zero, it ends up including a radical, but since x sub 1 is positive, that's still a real number.
04:00
So if k is zero, well, then x1 to the zero power is one, which is still a positive real number.
04:10
So what if k is negative? if k is negative, then this ends up with a fraction, would be one over, x1 to the k power, and that's still a real number.
04:24
So we're still good, and that is satisfied.
04:31
But we need to satisfy all 10 conditions.
04:36
So let's go to condition 3, axiom 3, commutativity of addition.
04:45
So what that's telling us is that x1 plus x sub 2 have to equal x sub 2 plus x sub 1.
05:00
Well, x1 plus x2 is defined as x sub 1 times x sub 2.
05:11
But since these are just real numbers, i can reverse the order x sub 2 times x sub 1.
05:17
And so back into our potential vector space, that's x sub 1 plus x sub 2.
05:28
And so, no, no, no, it's x sub 2 plus x sub 1.
05:33
I'm not sure how that happened.
05:38
And so, yes, that is satisfied.
05:41
So let's go down to axiom 4.
05:50
Associativity of addition.
05:52
So that's telling us that x1 plus x2 plus x3, and we have to be able to do 2 plus 3 first and then 1.
06:06
So let's do x1 plus x2 first.
06:09
That would be x1, x2 plus x3, which is going to give us x1, x2, x2, x3.
06:30
Now, according to the associative property, we can rearrange that to x2, x3, x1, which now we can separate to x, whoops, i tried to do green, x2, x3 plus x1, which is x2x3 plus x1, which is x2, x2 plus x3.
07:17
Oh, i mixed up my colors.
07:30
Which is what we wanted.
07:32
So we are good again.
07:34
That axiom is satisfied.
07:37
X, a4.
07:49
Okay, a5.
08:05
Existence of a zero vector.
08:07
I'm wondering about this one.
08:09
Existence of a zero vector.
08:13
So, these are positive numbers.
08:18
So i can't include zero.
08:27
So i'm thinking the only other reasonable candidates are either one or maybe infinity, but infinity is not even a real number.
08:41
So because infinity just represents going on and on.
08:47
The only possible candidate is one.
08:50
So is 1 our 0 vector? well, let's think about that.
09:04
And let's think about it in, maybe even in a6, but existence of an additive inverse.
09:32
So plus the inverse of x.
09:49
And i've just realized every time that i'm writing these red pluses really should be writing this.
10:05
A little bit sad that i didn't.
10:09
That could have been a little confusing, or maybe a lot confusing.
10:26
Well, that's going to be multiplying them together.
10:55
And so that didn't work out because i'm looking at, x plus the opposite of x equals the zero vector...