Question
Let $P$ and $Q$ be $3 \times 3$ matrices $P \neq Q$. If $P^{3}=Q^{3}$ and $P^{2} Q=Q^{2} P$, then determinant of $\left(P^{2}+Q^{2}\right)$ is equal to:(A) $-2$(B) 1(C) 0(D) $-1$
Step 1
We subtract the two equations to get $P^{3}-P^{2}Q=Q^{3}-Q^{2}P$. Show more…
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