Question
Let $P$ be a variable point on the ellipse $\frac{x^{2}}{25}+\frac{y^{2}}{9}=1$, with foci $F_{1}$ and $F_{2}$. If $A$ is the area of the triangle $P F_{1} F_{2}$, then the maximum value of $\frac{1}{3} A$ is
Step 1
The foci of the ellipse are at $F_{1}(-5,0)$ and $F_{2}(5,0)$. Show more…
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Key Concepts
Recommended Videos
(i) Find the area of the triangle inscribed in the ellipse $\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1$, eccentric angles of whose vertices are $\alpha, \beta$ and $\gamma$. (ii) Find the maximum area of a triangle inscribed in the ellipse $\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1$.
Use Lagrange multipliers to find the maximum area of a rectangle inscribed in the ellipse (Figure 16): $$\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1$$
DIFFERENTIATION IN SEVERAL VARIABLES
Lagrange Multipliers: Optimizing with a Constraint
Find the largest triangle that can be inscribed in the ellipse $\left(x^{2} / a^{2}\right)+\left(y^{2} / b^{2}\right)=1$ (assume, the triangle symmetric about one axis of the ellipse with one side perpendicular to this axis).
PARTIAL DIFFERENTIATION
Maximum and minimum problems with constraints; Lagrange multipliers
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