Question
Let $\vec{v}=\left\langle v_{1}, v_{2}\right\rangle$ be any non-zero vector. Show that $\frac{1}{\|\vec{v}\|} \vec{v}$ has length 1.
Step 1
The magnitude of a vector is given by the square root of the sum of the squares of its components. So, the magnitude of $\vec{v}$ is $\|\vec{v}\| = \sqrt{v_{1}^{2} + v_{2}^{2}}$. Show more…
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