Question
Let $x$ and $y$ be two real numbers such that $x>0$ and $x y=1$. The minimum value of $x+y$ is(a) 1(b) $1 / 2$(c) 2(d) $1 / 4$
Step 1
We can express $y$ in terms of $x$ as $y=\frac{1}{x}$. Show more…
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For all real $x$, the minimum value of $\frac{1-x+x^{2}}{1+x+x^{2}}$ is (A) 0 (B) $\frac{1}{3}$ (C) 1 (D) 3
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