00:01
So in this question we have given that refractive index n1 it is equals to 1 .30 and n2 it is equals to 1 .33 that is refractive index of air and refractive index of the water.
00:15
Okay.
00:16
And the angle of incident that is theta i it is given as 30 .0 degree with respect to the normal line.
00:24
So we have to determine the angle theta between reflected ray, reflected ray, reflected ray, and refracted ray, refracted ray.
00:35
So first of all, calculating the angle of refraction, that is theta r, so using sinai law, so we can write that n1, sitha i, this is equals to n2, sine theta r, okay? so from here we get theta r, it is equals to theta r, this will be equals to n1 by n2, sine theta i and this complete arc sign okay or we can write here that sign theta r so from here we can get theta r it is equal to arc sign of this complete value n1 by n2 sign theta i okay so substituting all the values so theta r it will be equals to arc sine of n1 which is one point triple zero n two which is 1 .33, sine, theta i which is 30 .0 degree...