Step 1:
We know that the stopping potential $V_s$ is given by the equation:
\[V_s = \frac{hc}{e} \left(\frac{1}{\lambda} - \frac{1}{\lambda_c}\right)\]
where $h$ is Planck's constant, $c$ is the speed of light, $e$ is the charge of an electron, $\lambda$ is the
Show more…